2x^2/5-5x^1/5=-3

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Solution for 2x^2/5-5x^1/5=-3 equation: 


x in (-oo:+oo)

(2*x^2)/5-((5*x^1)/5) = -3 // + 3

(2*x^2)/5-((5*x^1)/5)+3 = 0

(2*x^2)/5-x+3 = 0

2/5*x^2-x+3 = 0

DELTA = (-1)^2-(2/5*3*4)

DELTA = -19/5

DELTA < 0

x belongs to the empty set

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